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Len [333]
3 years ago
15

How in the world do I answer this problem??​

Mathematics
1 answer:
galben [10]3 years ago
4 0

Answer:

22

Step-by-step explanation:

ST is y and SU is 2y-4.

Note that SU = ST + TU = y + 18

So we have 2y - 4 = y + 18

2y - 4 = y + 18

2y      = y + 22

y        = 22

So ST is 22.

:)

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The triangle below is equilateral. Find the length of side x to the nearest tenth.
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Answer:

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Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}

x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

x^{2} =10-\frac{10}{4}

x^{2} =\frac{15}{2}

x=\sqrt{\frac{15}{2} }

This approximately equals 2.738

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