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Fed [463]
2 years ago
12

How many turning points will a quartic fumction with four real zeros have?

Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

upto four roots or zero......

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Next, find the length of BC. Place point F at (4,4), and draw BF and FC. Find BF and FC using the coordinates of B, C, and F. Th
hammer [34]

9514 1404 393

Answer:

  BC = 5

Step-by-step explanation:

Of course, this geometry program can tell you the length of BC.

__

If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...

  BF = 4 -1 = 3

  FC = 4 -0 = 4

  BC² = BF² +FC²

  BC² = 3² +4² = 9 +16 = 25

  BC = √25

  BC = 5

7 0
3 years ago
! et up your proportions) Eduardo counted eight seconds between seeing lightning and hearing thunder, and he knew that the light
vova2212 [387]

Answer:

1 mile away this is right

3 0
2 years ago
27 divided by 89,420 remainder as a faction?
LUCKY_DIMON [66]
No not really because 89,420 cant be bigger than 27
4 0
3 years ago
twice the sum of a number and 2 is equal to three times the difference of the number and 3. Find the number
Lana71 [14]
2(x+2)=3(x-3)
2x+4=3x-9
2x=3x-13
-x=-13
x=13

The number is 13
3 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
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