Answer:
∠ACB = 28.5
Step-by-step explanation:
In triangle ABC,
angle CAB = x-3
angle ABC = 4X-3
It is also given that AB=CB
We know that if two sides of any triangle are equal then corresponding sides must also be equal.
Hence
angle ACB = angle CAB
angle ACB = x-3 {Given that angle CAB = x-3 }
We know that sum of all three angles of a triangle is 180 degree so let's add given angles
angle ACB + angle CAB + angle ABC = 180
(x-3) + (x-3) + (4x-3) = 180
x-3 + x-3 + 4x-3 = 180
6x-9 = 180
6x = 180+9
6x = 189
x = 189/9
x= 31.5
Now plug value of x into
angle ACB = x-3 = 31.5-3 = 28.5
Hence final answer is
∠ACB = 28.5
The midpoint is C, (-0.5,0.5)
Find the middle between the x and y coordinates and that is the midpoint
me neither but this is what i got
3n² p⁴
F(x)=1-x² and g(x)=√(11-4x)
(g+f)(2)=>
1-(2)²+√(11-4(2))
=√3-3
(f/g)(-1)
(1-(-1)²)/(√(11-4(-1))
=0
(g-f)(-1)
√(11-4*-1)-(1-(-1)²
=√15
(g×f)(2)
1-(2)²×√(11-4(2))
-3√3
