Question

PLEASE HELP Consider the three functions below.

Answer 1

$f(x)=\frac{-6}{11}*(\frac{11}{2} )^{x}$

Domain : All real numbers since this is an exponential function.

Range : (-∞,0)

$f(x)=\frac{6}{11}*(\frac{11}{2} )^{-x}$

Domain : All real numbers since this is an exponential function.

Range : (0,∞)

$f(x)=\frac{-6}{11}*(\frac{11}{2} )^{-x}$

Domain : All real numbers since this is an exponential function.

Range : (-∞,0)

So Option C  : )The ranges of f(x) and h(x) are different from the range of g(x).

Answer 2

If these are supposed to be exponential functions

$\displaystyle f(x)=-\frac{6}{11}\left(\frac{11}{2}\right)^{x}\\\\g(x)=\frac{6}{11}\left(\frac{11}{2}\right)^{-x}\\\\h(x)=-\frac{6}{11}\left(\frac{11}{2}\right)^{-x}$

Then they are all defined for all real numbers, so all have the same domain. The range of f and h will be (-∞, 0) and the range of g will be (0, ∞), so these are different.

The appropriate statement choice is ...

... C)The ranges of f(x) and h(x) are different from the range of g(x).