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3 years ago

2d+7/6-d-5/3=0 Tell me the answer

Mathematics

1 answer:

Andrej [43]3 years ago

4 0

Answer:

D=1/2

Step-by-step explanation:

Multiply the numbers

Subtract the numbers

Combine like terms

put 1/2 to the two parts of the equation

last but not least, simplify

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A student determined that the area of the segment of c shown above is Asegment = 137.71 ft2. The student's work is shown below.

ivolga24 [154]

Answer:

Option D. The student did not use the correct formula to calculate the area of the segment

Step-by-step explanation:

step 1

Find the area of the isosceles triangle

Applying the law of sines

$A=\frac{1}{2}(12^{2})sin(60\°)=62.35\ ft^{2}$

step 2

Find the area of the sector

The area of the sector is 1/6 of the area of the circle

$A=\pi r^{2}/6$

substitute the value

$A=(3.14)(12)^{2}/6=75.36\ ft^{2}$

step 3

Find the area of the segment

The area of the segment is equal to the area of sector minus the area of triangle

$A=75.36\ ft^{2}-62.35\ ft^{2}=13.01\ ft^{2}$

therefore

The student did not use the correct formula to calculate the area of the segment

4 0

3 years ago

I reallyyy just need the answer fast!

Mars2501 [29]

Answer:

68×32= 2176

Step-by-step explanation:

5 0

3 years ago

Please help! I will give 20 points

Svetllana [295]

Answer:

45 = (45+18)

55 = (55+y)

55+y= (63 ×55) /45

y= 77- 55

y = 22 cm

45 = 63

x = 70

x= (45×70)/63

x = 50 cm

3 0

3 years ago

Read 2 more answers

Anthony has $3750 that he wants to invest. He plans to leave the money there for 9 years. If his investment gets 6.35% interest

xenn [34]

Answer:

$A= P(1+\frac{r}{n})^{nt}$

P = 3750

r = 6.35% = 0.0635

n = 365

t = 9

$A= 3750(1+\frac{0.0635}{365} )^{365*9}\\\\$

$= 3750(1+\frac{0.0635}{365})^{3285} = 6640.63$

Answer = $6641

5 0

3 years ago

The estimated velocity v (in miles per hour) of a car at the end of a drag race is v = 234 √p ÷ w 3 , where p is the horsepower

Anastaziya [24]

Answer:

The velocity of the car at the end of drag race is 183 miles per hour.

Step-by-step explanation:

We are given the following in the question:

$v = 234 \bigg(\dfrac{p}{w}}\bigg)^{\frac{1}{3}}$

where v is the velocity of the car at the end of drag race, p is the horsepower of the car and w is the weight of car.

We need to approximate velocity of the car at the end of a drag race when car has a horsepower of 1311 and weighs 2744 pounds.

Putting values in the equation, we get,

$v = 234\bigg(\dfrac{1311}{2744}\bigg)^{\frac{1}{3}}\\\\v = 182.93\\v\approx 183\text{ miles per hour}$

Thus, the velocity of the car at the end of drag race is 183 miles per hour.

3 0

4 years ago

2d+7/6-d-5/3=0 Tell me the answer ​

2d+7/6-d-5/3=0 Tell me the answer