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andrey2020 [161]
3 years ago
6

2. Write the equation of the line of best fit using the slope-intercept formula $y = mx + b$. Show all your work, including the

points used to determine the slope and how the equation was determined.

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

y=x

Step-by-step explanation:

By using the (y2-y1)/(x2-x1), you can find y=mx+b

Points: (30,30) and (60,60)

(60-30)/(60-30)= 30/30=1

Your m value (slope) is 1.

For the y-intercept, your value is 0

The full answer is y=x

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The length of the base of an isosceles triangle is x. The length of a leg is 4x-6. The perimeter of the triangle is 60. Find x.
lbvjy [14]

Answer:

Perimeter of a triangle = add all sides

Both the legs of the isosceles triangle are always EQUAL.

x+4x-6+4x-6 = 60

9x-12 = 60

9x = 60+12

9x = 72

x = 8

3 0
3 years ago
Find the difference and write it in simplest form 11 1/9 - 3 2/3
mezya [45]

Answer: 7 4/9

Step-by-step explanation:

Find least common denominator of 3 and 9, which is 9. So, 11 1/9 - 3 6/9 = 7 4/9

8 0
3 years ago
Rationalize <br><img src="https://tex.z-dn.net/?f=1%20%5Cdiv%20%20%5Csqrt%7B%7D3%20-%20%20%5Csqrt%7B2%7D%20" id="TexFormula1" ti
Marat540 [252]

Answer:

1 \div \sqrt{}3 - \sqrt{2}

\frac{1 -  \sqrt{2} \sqrt{3}  }{ \sqrt{3} }

\frac{(1 -  \sqrt{6}) \sqrt{3}  }{ \sqrt{3} \sqrt{3}  }

\frac{ \sqrt{3}  -  \sqrt{6 \times 3} }{3}

\frac{ \sqrt{3} -  3\sqrt{2}  }{3}

is a required answer.

8 0
3 years ago
Whoever can answer will get brainliest. ​
juin [17]
#1 is 560 #2 is 105 #3 is 1980 #4 is 1122 hope it helps
4 0
3 years ago
If AD/DB = AE/EC, then line segment (?) is parallel to line segment (?) .
olga_2 [115]

Answer:

Step-by-step explanation:

In ΔABC, we have

\frac{AD}{DB}=\frac{AE}{EC}

The Converse of the basic proportionality theorem states that if a line divides two sides of a triangle in same ratio then the line must be parallel to the third side.

Now, it is given that \frac{AD}{DB}=\frac{AE}{EC}, this implies that line segment DE divides AB and AC in the same ratio.

Thus, by converse of basic proportionality theorem  

line segment DE= line segment BC.

Therefore, if  \frac{AD}{DB}=\frac{AE}{EC},then line segment DE is parallel to line segment BC .

4 0
3 years ago
Read 2 more answers
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