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worty [1.4K]
3 years ago
10

Find the absolute value. What is the absolute value of four

Mathematics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

whats the graph???

Step-by-step explanation:

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Please look at the attached file, it may help you

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3 years ago
3/5 of an apple tree is unripe what percent of it is ripe?
trapecia [35]
If 3/5 of the tree is unripe, then 2/5 of the tree is ripe.

2/5 = 0.4

0.4 x 100 = 40% of the tree is ripe
4 0
3 years ago
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⎧ g(1)=−19 g(n)=g(n−1)+6 ​Find an explicit formula for g(n)
EastWind [94]

Answer:

g(n) = 6n - 25.

Step-by-step explanation:

We have an arithmetic sequence here.

The common difference (d)  is g(n) - g(n - 1) = 6.

The first term a1 = -19 so the formula is:

a1 + (n - 1)d

-19 + (n - 1)6

= 6n - 19 - 6

= 6n - 25.

6 0
3 years ago
(1) In a bag of 10 donuts: every donut looks the same but 6 of them have the chocolate flavor and the other 4 have the vanilla f
vampirchik [111]

Answer:

a) 0.432, b) 0.1029 and c) 0.08

Step-by-step explanation:

a) what is the probability that you get 2 chocolate-flavor donuts and one vanilla-flavor donut?

Observe that there are 3 possible ways for this to happen. Getting a vanilla donut first, second or third. And every of this cases has a probability of

\frac{6}{10}\times \frac{6}{10} \times \frac{4}{10}=\frac{144}{1000}

Therefore, the probability of a) to happen is given by:

3\times \frac{144}{1000}=\frac{432}{1000}=0.432

b) What is the probability that he gets 5 chocolate-flavor donuts?

Observe that:

  • There are {10 \choose 5} ways to choose 5 chocolate donuts between 10
  • The probability of each one of those cases to happen is given by (0.3)^5\times(0.7)^5

Therefore the probability of b) to happen is given by:

{10\choose 5}\times(0.3)^5\times(0.7)^5=252\times(0.00243)\times(0.16807)\approx0.1029

c) what is the probability that he eats 10 donuts that day?

Observe that, in order for the donut lover to eat exactly 10 donuts 2 things must happen

  1. He should have eaten 9 donuts from which 3 of them were chocolate-flavored.
  2. The 10th donut he ates must be a chocolate-flavored one.

Then we proceed to compute the probability of 1 the same way as in b).

  • There are {9 \choose 3} ways to choose 3 chocolate donuts between 9
  • The probability of each one of those cases to happen is given by (0.3)^3\times(0.7)^6

Therefore the probability of 1 to happen is given by:

{9\choose 3}\times(0.3)^3\times(0.7)^6=84\times(0.027)\times(0.117649)\approx0.2668

Finally the probability of 2 to happen is known to be 0.3 and, as 1 and 2 are independent events, the probability of both to happen is the multiplication of the probabilities. Then, the answer for c) is:

(0.3)\times(0.2668)\approx0.08

3 0
3 years ago
Which expression can be used to find the difference of the polynomials? (10m – 6) – (7m – 4)
My name is Ann [436]
I thinks it is D not sure



4 0
3 years ago
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