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Aliun [14]
3 years ago
7

Can someone help Hello I’m struggling over here

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0

Answer:

c)  2.25 L

Step-by-step explanation:

Amount of pineapple juice = 3/4 of 3 L

                                              = 0.75 * 3

                                               = 2.25 L

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What is the value of y2 – x2 when y = 6 and x = 5?
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Answer:

y^2 - x^2 = 11

Step-by-step explanation:

y^2 - x^2 = ?

Substitute.

y = 6

x = 5

Becomes:

6^2 - 5^2 = ?

Solve.

6^2 = 6 x 6

6 x 6 = 36

5^2 = 5 x 5

5 x 5 = 25

36 - 25 = 11

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The local humane society currently has 60 cats if 300 animals are in the shelter what percent are the cats
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0.2 is the same thing as 20%.
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3 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
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65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

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Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

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Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
To multiply a whole number by a fraction, you can first write the whole number as a fraction by placing the whole number in the
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No. the product stays the same because it is still the same number, just in fraction form.

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