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DerKrebs [107]
3 years ago
14

Find the values of x and y. Pls helpI’m helpless at math

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

  • x = 1
  • y=\frac{\sqrt{3}}{2}  

Step-by-step explanation:

From the given right-angle triangle

The angle = ∠60°

  • The adjacent to the angle ∠60° is 1/2.
  • The opposite to the angle ∠60° is y.

The hypotenuse = x

<u>Determining the value of x:</u>

Using the trigonometric ratio

cos 60° = adjacent / hypotenuse

substituting adjacent = 1/2 and hypotenuse = x

cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}

\cos \left(60^{\circ \:}\right)=\frac{1}{2x}

\frac{1}{2}=\frac{1}{2x}          ∵ cos (60°) = 1/2

2x=2

Dividing both sides by 2

\frac{2x}{2}=\frac{2}{2}

Simplify

x=1

Thus, the value of hypotenuse x is:

x = 1

<u>Determining the value of y:</u>

Using the trigonometric ratio

sin 60° = opposite / hypotenuse

As we have already determined the value of hypotenuse x = 1

substituting opposite = y and hypotenuse = 1

sin 60° = y/1

y = 1 × sin 60°

y=\frac{\sqrt{3}}{2}       ∵  \sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}

Therefore, the value of y is:

y=\frac{\sqrt{3}}{2}      

Summary:

  • x = 1
  • y=\frac{\sqrt{3}}{2}    
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