Answer:
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Step-by-step explanation:
The null hypothesis is:

The alternate hypotesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.
This means that 
Assume the population standard deviation is 6.2 weeks.
This means that 
Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
We have to find the pvalue of Z, looking at the z-table, when
. It if is lower than 0.05, it provides evidence.



has a pvalue of 0.0113 < 0.05.
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Answer:
x = -10
Step-by-step explanation:
First you have to isolate x
then you have to add 3 on the other side.
so yeahh!!
(-5/8)(X) = -0.4
(-5/8)(X) = -4/10
X = (-4/10) / (-5/8)
X = (4/10) / (5/8)
X = (4/10)(8/5)
X = (2/5)(8/5)
X = 16/25
Letter D
60 total fourth graders and 43 are girls. To find the number of boys, subtract.
60 - 43 = 17 boys
If 5 girls were absent, subtract.
43 - 5 = 38 girls present
If 4 boys were absent, subtract.
17 - 4 = 13 boys present
Therefore, there were 13 boys present.
Best of Luck!