All categories

3 years ago

Write an equation and solve round to the nearest hundredth when necessary 19 is what percent of 40

Mathematics

1 answer:

german3 years ago

4 0

Answer:

Final answer is 47.5%.

Step-by-step explanation:

Let the missing percent is x.

Then x percent of 40 can be written as: $40\cdot\frac{x}{100}$ .

Given that resulting percent value is 19.

So we can set both equal.

$40\cdot\frac{x}{100}=19$

$40x=19\cdot100$

$40x=1900$

$x=\frac{1900}{40}$

$x=47.5$

So the final answer is 47.5%.

You might be interested in

Y=[? ]°<br><br> Please help me!!

chubhunter [2.5K]

“y” is a part of a straight angle, so
131 + y = 180
y = 180 - 131
y = 49 [degrees].

3 0

2 years ago

Kayla is building a custom frame using reclaimed wood. She needs the frame to be 14 1/2 inches wide by 9 1/4 inches long. She ha

Alborosie

She will have 6 and 1/4 inches of wood left. 23 3/4 - 30 is 6 1/4.

6 0

3 years ago

We want to factor the following expression: (x+7)^2+2y(x+7)+y^2 which patter can we use to factor the espression? U and V are ei

Lostsunrise [7]

Answer:

A. (U+V)^2 or (U-V)^2

Step-by-step explanation:

5 0

3 years ago

In order for the table below to show exponential decay, what must the value of d be in the table below?

Eduardwww [97]

Let x represent the domain
Let y represent the range.

Assume that y =a*b⁻ˣ

Set x=0:
a*b⁰ = 32
a = 32

Set x=1:
32*b⁻¹ = 24
32 = 24b
b = 32/24

Set x=2:
d = 32*(32/24)⁻²
= 32*(24/32)²
= (32*24*24)/(32*32) = 24²/32 = 576/32
= 18

Answer: 18

9 0

3 years ago

Read 2 more answers

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

3 years ago