Hello there!
To find the increasing intervals for this graph just based on the equation, we should find the turning points first.
Take the derivative of f(x)...
f(x)=-x²+3x+8
f'(x)=-2x+3
Set f'(x) equal to 0...
0=-2x+3
-3=-2x
3/2=x
This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
Since the leading coefficient is -1, as x approaches ∞, f(x) approaches -∞ Because the exponent of the leading term is even, the end behavior of f(x) as x approaches -∞ is also -∞.
This means that the interval by which this parabola is increasing is...
(-∞,3/2)
PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.
I really hope this helps!
Best wishes :)
Answer:
(9,3)
Step-by-step explanation:
You can just substitute the answer choices in to the equation and see what option works for both equations.
The answer would be 49,588.5 my good sir. Good job trolling me.
I would think that a dozen(12) would be 20 bc if the bakery is selling half a dozen(6) for $10 then he would double it bc if u buy two half dozen boxes it will come to $20 hope u get what I'm saying
Hope I helped good luck have a nice nite and I hope u enjoy the rest of ur weekend
