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valina [46]
3 years ago
8

Classify the pair of angles. Then find the value of x.

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

3) x = 50, vertical angles.

4) x = 20, supplementary angles

5) x = 14, complimentary angles

Step-by-step explanation:

<h3>3)</h3>

<em>vertical angles.</em>

<em>vertical angles are equal.</em>

<em>so, you can make this equation:</em>

67 = x + 17

<em>subtract 17 from both sides of the equation</em>

67 - 17 = x + 17 - 17

67 - 17 = x

50 = x

<h3>4)</h3>

<em>supplementary angles</em>

<em>supplementary angles add up to 180</em>

<em>so, you can make this equation:</em>

7x + 40 = 180

<em>subtract 40 from both sides of the equation</em>

7x + 40 - 40 = 180 - 40

7x = 180 - 40

7x = 140

<em>divide both sides by 7</em>

7x/7 = 140/7

x = 140/7

x = 20

<h3>5)</h3>

<em>complimentary angles</em>

<em>complimentary angles add up to 90</em>

<em>so, you can make this equation:</em>

4x + 34 = 90

<em>subtract 34 from both sides of the equation</em>

4x + 34 - 34 = 90 - 34

4x = 90 - 34

4x = 56

<em>divide both sides by 4</em>

4x/4 = 56/4

x = 56/4

x = 14

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Answer:

a. 28.8

Step-by-step explanation:

Using the theorem of similarity, the following equation can be generated:

\frac{x}{12} = \frac{25 + 35}{25}

Solve for x

\frac{x}{12} = \frac{60}{25}

Cross multiply

x*25 = 60*12

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Divide both sides by 25

x = 28.8

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3 years ago
The sum of four consecutive integers is 48. What is the smallest of four integers?<br><br> Plz hurry
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Answer:

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Step-by-step explanation:

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x−3,2x^2−4x+30

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AB= 4x + 7 and BC = 20x - 5 <br> AB ~= BC
Mariana [72]

The value of the variable x is 3/4

<h3>What are congruent segments</h3>

Congruent segment are segments with equal or congruent lengths.

From the information given, we have that line AB is approximately equal to line BC. This is represented as;

AB = BC

Where;

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Now, let's equate the expressions

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collect like terms

4x - 20x = - 5 - 7

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Make 'x' the subject of formula

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Read 2 more answers
Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
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