First case:
average of test score =70
number of students =p
total score of 'p' students = ( average of test score)*( number of students)
total score of 'p' students =70p
Second case:
average of test score =92
number of students =n
total score of 'n' students = ( average of test score)*( number of students)
total score of 'n' students =92n
total number of students = p+n
total average score =86
so, total score =86(p+n)
total score = total score of 'p' students +total score of 'n' students
now, we can simplify it
now, we can find p/n
................Answer
Answer:
2 numbers that multiply to make -21 = 3 x (-7)
2 numbers that add up to -4 = 3 - 7
Step-by-step explanation:
2 numbers that multiply to make -21 = 3 x (-7) = -21
2 numbers that add up to -4 = 3 - 7 = -4
Answer:
Step-by-step explanation:
I used calculus for this, as I'm not sure there's any other way to do it and to do it as easily. This is the volume of a solid found by using the disk method of rotation:
![V=\pi\int\limits^a_b {[R(x)]^2-[r(x)]^2} \, dx](https://tex.z-dn.net/?f=V%3D%5Cpi%5Cint%5Climits%5Ea_b%20%7B%5BR%28x%29%5D%5E2-%5Br%28x%29%5D%5E2%7D%20%5C%2C%20dx)
where R(x) is the outer shell of the solid and r(x) is the space inbetween the solid and the axis of rotation. There is no space between the solid and the axis of rotation, so r(x) = 0. R(x) is the height of the solid which is 3. Therefore, f(x) = 3 and that's the function we put into the formula with the lower bound of 3 and the upper bound of 5:
and
and integrating:
and using the First Fundamental Theorem of Calculus:
V = π(9(5) - 9(3)) and
V = π(45 - 27) so
V = 18π units cubed or in decimal format,
V = 56.549 units cubed
Answer:
Part 1
Given equation:
C(t) = -0.30 (t – 12)² + 40
For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2
For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40
For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2
Part 2
attached below
Part 3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32
Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104
5, 6 and 7, should be simplish
good luck, i hope this helps :)
Step-by-step explanation:
