Formula : $EBM =z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$ , where $\alpha=$ significance level , $\sigma =$ Population standard deviation, n= sample size.

As per given, n= 22

$\sigma = 2$

Critical z- value for 90% confidence level : $z_{\alpha/2}=1.645$

Then,

$EBM =(1.645)\dfrac{2}{\sqrt{22}}\\\\=(1.645)\dfrac{2}{4.690416}\\\\\approx0.701$

Hence , error bound (EBM) of the confidence interval with a 90% confidence level= ± 0.701

5 0

3 years ago

Nickel-63 has half-life of about 96 years. after 336 years,about how many milligrams of an 800 mg sample will remain?

vagabundo [1.1K]

F=ar^t if the half-life is 96 years...

.5=r^96

ln(.5)=96lnr

ln(.5)/96=lnr

r=e^((ln.5)/96)

f=800e^(336(ln.5)/96)

f=70.71

So about 71mg will remain after 336 years.

5 0

3 years ago

Read 2 more answers

What is a 20% decrease followed by 40% increas

qaws [65]

i think its 112%

am i right?

7 0

3 years ago

What is 1546 divided by 12

Flauer [41]

1546/12 = 128.3333333333333333333333333333333333333

8 0

3 years ago

Simplify the expression 7h+​(−6.9d​)−14+5d−2.9h

Simplify the expression 7h+(−6.9d)−14+5d−2.9h