1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solniwko [45]
3 years ago
8

Easy points for those who are good at math!

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

<u>Answer:</u>

The answer is A) y = -7x - 7.

<u>Step-by-step explanation:</u>

First, you need to subtract '7x' from both sides, and once that is done, the equation is in slope-intercept form because it is in y=mx+b form. I'll attach a photo below that explains my process! :) And another possible answer would be y = 7x + 7, but that is not an option listed above.

<em>Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day, and good luck on your assignment. :)</em>

You might be interested in
I need help on this math problem:
sertanlavr [38]

Answer:

E

Step-by-step explanation:

11x-4<15

11x<11

x<1

12x-7>-25

12x>-18

x>-3/2

x<1 or x>-3/2, that covers the whole x-axis domain

5 0
3 years ago
Read 2 more answers
Choose the best description for the real number 44/3
Nimfa-mama [501]
Forty four divided by three is 14 1/3
3 0
3 years ago
Suppose p varies directly with d and p=3 when d=5. What is the value of d when p=12
ololo11 [35]

Answer:

Answer: <u> </u><u> </u><u>d</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u>

Step-by-step explanation:

{ \rm{p \:  \alpha \: d}} \\  \\ { \rm{p = kd}}

k is a constant of proportionality

• When p = 3, d = 5.

{ \rm{3 = (k \times 5)}} \\  \\ { \rm{k =  \frac{3}{5} }}

• Therefore, equation becomes;

{ \rm{p =  \frac{3}{5} d}}

• Let's find d when p is 12;

{ \rm{12 =  \frac{3}{5}d }} \\  \\ { \rm{d =  \frac{12 \times 5}{3} }} \\  \\ { \underline{ \underline{ \rm{ \:  \: d = 20 \:  \: }}}}

8 0
2 years ago
The owner of Dennis's garage wants to fill a 55 gallon drum with a 20% winter mixture of antifreeze for his customers. Denis wan
fredd [130]

Answer:

6.1 gallons of 100% antifreeze and 48.9 gallons of 10% antifreeze

Step-by-step explanation:

Let the amount of 100% antifreeze be x gallon

let the amount of 10% antifreeze be y gallon

total amount to drum = 55 gallons

therefore x + y = 55 -------------------------------Eqn 1

    100%(x) + 10(y) = 20%(55)

     x + 0.1y = 11--------------------------------------Eqn 2

Both equations are solved simultaneously

From eqn 1 x = 55-y

Substitute x = 55-y into eqn 2

55-y+0.1y = 11

collecting like terms

44 = 0.9y

y = 48.88889

x = 55- 48.88889 = 6.11111 gallons

Therefore 6.1 gallons of 100% antifreeze and 48.9 gallons of 10% antifreeze

7 0
3 years ago
Whats the halfway point from 32 to 16?
irina1246 [14]
The halfway point is 24

• First, add the two numbers: 32 + 16 = 48
• Second, divide the total by 2: 48/2 = 24

7 0
3 years ago
Other questions:
  • What is the probability of spinning different numbers when the spinner below is spun twice​
    10·1 answer
  • What is the greatest whole number that rounds to 621,860?
    11·1 answer
  • Ashley Harrison takes out a $100,000 mortgage. The total amount of interest for 30 years is $90,000. What is the payment per mon
    9·2 answers
  • The proctoct of 5 and a odd number will end in
    13·1 answer
  • Find the mean, median, mode for 41,41,41,42,42,43,43,43,43,45,45,45,46,46,46,46,46,46,46,49,49,50,51,51,53,54,55,55,56,56,57
    12·1 answer
  • What is the expression in factored form? 9x^2-12x+4​
    9·2 answers
  • Find the area of the shaded polygons
    10·1 answer
  • Maria ran at a rate of 3.4 miles per hour for 6.8 hours. How many miles did she run in total?
    9·1 answer
  • Write the following expression using symbolic language.
    14·1 answer
  • 3% of a university's freshman class are majoring in Computer Science. If 231 students in the freshman class are Computer Science
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!