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kaheart [24]
2 years ago
15

Based on what you know now, how are linear and exponential functions alike?

Mathematics
1 answer:
Ainat [17]2 years ago
5 0

Answer:

They're similar in that they both have to maintain a steady rate of rise as they grow. While graphing, you can't adjust the slope or exponent after traveling up a graph.

Step-by-step explanation:

You might be interested in
Evaluate the following expression. Round to the nearest hundredth when necessary.<br><br> 6³ - 18
SSSSS [86.1K]

Answer:

198

Step-by-step explanation:

Because 6 to the power of three is 6 x 6 x 6 = 216 - 18 = 198

8 0
3 years ago
Can I get a help please ​
iogann1982 [59]

Answer:

middle graph

Step-by-step explanation:

Soluton

The  second (middle ) graph is the only one that works.

  • First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ -  1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
  • Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.

6 0
1 year ago
Choose two angles that are each separately alternate exterior angles with 412.
Alborosie

Answer:

∠2 and ∠5

Step-by-step explanation:

we know that

<u>Alternate Exterior Angles</u> are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal

In this problem

∠12 and ∠2 are alternate exterior angles

∠12 and ∠5 are alternate exterior angles

therefore

∠2 and ∠5 are each separately alternate exterior angles with ∠12

6 0
3 years ago
Which expression is equivalent to
ozzi
The answer for the question shown above is the first option: x^2(x^2)^1/4
 When you simplify the expression, you obtain the equivalent expression:

 (x^10)^1/4
 [(x^8)(x2)]^1/4
 x^2(x^2)^1/4

 Therefore, the asnwer is the option mentioned before.
5 0
3 years ago
Read 2 more answers
Two show your work questions
Svet_ta [14]

Answer:

x = 1; y = 1; z = 0

Step-by-step explanation:

First problem:

First equation minus second equation: 3y + 2z = 3      Eq. A

Second equation plus third equation: 2y + 4z = 2        Eq. B

-2 times Eq. A plus Eq. B: -4y = -4

y = 1

Substitute y = 1 in Eq. A: 3 + 2z = 3

2z = 0

z = 0

Substitute z = 0 and y = 1 in original first equation:

-2x + 2 + 0 = 0

-2x = -2

x = 1

Answer: x = 1; y = 1; z = 0



5 0
3 years ago
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