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amm1812
3 years ago
8

Find the area of this parallelogram maths watch

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
6 0

Answer:

pls where is d questiom

Step-by-step explanation:

I can't see any question

Elodia [21]3 years ago
6 0

Answer:

where is it

Step-by-step explanation:

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If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?
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(1,1)

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3 years ago
How do i round 4,398,202 to the nearest 100
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When you round 4, 398, 202 to the nearest 100 it means to ignore the 4,398 and just look at 202. You could either round to 200 or 300 since you want to round to the nearest 100. Since the ones place is 2, you round the number to 200.

Answer: 4,398,200
8 0
4 years ago
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Classify △NOP with vertices N(–4, 2), O(–1, 6), and P(–1, –2) according to its sides. Then find its perimeter (HINT - it may be
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Step-by-step explanation:

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3 years ago
4. The figure shows a rectangle with a width of 6k inches. The length of the rectangle is 4 inches shorter than the width.
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Step-by-step explanation:

7 0
3 years ago
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(a) Show that the volume of a metal sphere of radius 15 cm is 14140 cm”, correct to 4 significant
Sladkaya [172]

Answer:

a) The volume of the sphere is approximately 14,137.16694 which is 14,140 cm³ correct to 4 significant figures

b) The volume of water required to fill the tank is approximately 103,670 cm³

Step-by-step explanation:

a) In the question, the radius of the sphere, r = 15 cm

The formula for the volume, 'V', of a sphere is given as follows;

V = \dfrac{4}{3} \times \pi \times r^3

Where;

r = The radius of the the sphere

V = The volume of the sphere

Plugging in the value for the radius, 'r', of the sphere, in the equation for, 'V', we get;

V = \dfrac{4}{3} \times \pi \times 15^3 \approx = 14,137.16694

Therefore;

The volume of the sphere to 4 significant figures is V ≈ 14,140 cm³

b) The parameters of the cylindrical tank are;

The height of the cylindrical tank, h = 60 cm

The radius of the cylindrical tank, r = 25 cm

The volume of a cylinder, V = π·r²·h

∴ The volume of the cylindrical tank without water, 'V_t', is given as follows;

V_t = π × (25 cm)² × 60 cm ≈ 117809.72451 cm³

The volume of water, V_{water}, required to fill the tank with the sphere of volume 'V' placed inside is given as follows

V_t = V + V_{water}

∴ V_{water} = V_t - V

From which we get;

V_{water} ≈ 117809.72451 cm³ - 14,140 cm³ = 103,669.72451 cm³ ≈ 103,670 cm³

The volume of water required to fill the tank, V_{water} ≈ 103,670 cm³.

8 0
3 years ago
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