Answer:
5 cm
Step-by-step explanation:
The distance a coiled spring stretches varies directly with the amount of weight hanging on the spring.
Distance = D
Weight = W
Hence:
D ∝ W
D = kW
Where k is constant of proportionality
Step 1
We solve for k
If a spring stretches 2 cm when a 30 gram weight is hung from it.
2 = 30k
k = 2/30
k = 1/15
Step 2
how far will it stretch when a 75 gram weight is hung from the spring?
D = kW
We are solving for D
k = 1/15
D = 1/15 × 75
D = 5 cm
The spring would stretch 5cm with a weight of 75 gram.
Answer:
sccccccccccccccccccccccccccccccccccccccccccafda
Step-by-step explanation:
fsdfsafvsafsdgarrgegrgergrg
Answer:
For 1 miles distance: 7/10 of a mile she runs and 3/10 she walks.
For 4 miles distance (4 times the previous distance) she will run:
4*(7/10) = 18/20 = 2.8 miles
and walk:
4*(3/10) = 12/10 = 1.2 miles.
Answer:
824.10
Step-by-step explanation:
Answer:
50%
Step-by-step explanation:
6 numbers on a die, 3 of them are odd.
3/6=1/2=50%
