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ANEK [815]
3 years ago
9

Which one if these sets of ordered pairs is not a function ? help please

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0
A function has only one y-value for each x-value. If you find a set that has an x-value used more than once, it is not a function, because that x-value is now paired with more than one y-value.

The fourth answer is the only one that has the same x-value used more than once.

Side note: Don’t worry if a y-value is used more than once. That’s totally fine. It’s all about the x-values.
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(N * 3) + 6 - (n * 2) = n + 3 what is value of n
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The function V(t)=1,000(1.06)^t models the value of an investment after t years. What does the ".06" represent in the function?
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Answer:

A

Step-by-step explanation:

Looking at the function, we have;

V(t) = 1,000(1.06)^t

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V = I(1 + r)^t

where V is the value of the investment after some certain number of years

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Let’s now re-write what we can deduce in the question.

This is;

V(t) = 1000(1 + 0.06)^t

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8 0
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iragen [17]

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Step-by-step explanation:

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