3 years ago

Perform (3x^3 – 2x^2 + 3x – 4) ÷ (x – 3) to find the value of the remainder.

Mathematics

2 answers:

BartSMP [9]3 years ago

8 0

I believe the answers is B

Svetach [21]3 years ago

8 0

Answer:

a) 68

Step-by-step explanation:

using the remainder theorem.

3x^3 - 2x^2 + 3x - 4 ÷ x - 3

p(a) = 3x^3 - 2x^2 + 3x - 4

p(3) = 3(3)^3 - 2(3)^2 + 3(3) - 4

= 3(27) - 2(9) + 9 - 4

= 81 - 18 + 9 - 4

= 68

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