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Tanya [424]
3 years ago
15

Item 3

Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

OPTION B AND D..

<em>A</em><em> </em><em>K</em><em>G</em><em> </em><em>I</em><em>S</em><em> </em><em>G</em><em>R</em><em>A</em><em>T</em><em>E</em><em>R</em><em> </em><em>T</em><em>H</em><em>A</em><em>N</em><em> </em><em>G</em>

<em>A</em><em>N</em><em>D</em><em> </em><em>G</em><em> </em><em>I</em><em>S</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>S</em><em>M</em><em>A</em><em>L</em><em>E</em><em>R</em><em> </em><em>T</em><em>H</em><em>E</em><em>N</em><em> </em><em>K</em><em>G</em>

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Answer:

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How do you solve this question<br><br> /
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe
k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

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Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

N=(25+60)+(40+60) - 60\\N= 125

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%

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Step-by-step explanation:

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