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3 years ago

Item 3

Mathematics

1 answer:

eimsori [14]3 years ago

6 0

Answer:

OPTION B AND D..

A KG IS GRATER THAN G

AND G IS 1000 SMALER THEN KG

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Pls help, my teacher told me to translate this as an assignment so pls help.

Shtirlitz [24]

Answer:

the first easy assignment for aii the students

the first day of school is go in to be in a while

Step-by-step explanation:

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3 years ago

plz give me correct answer and no spammng,alphabets,links,website,sorry,i don't know,have a great day,plz appreciate my work the

kramer

Answer:

1. (7/8) 2. (4/5)

Step-by-step explanation:

brainly.com/question/15513807 (1st question)

A torch and a battery cost 2.50 altogether. The torch costs 1.50 more than the battery.

Torch (t) = b+1.50

Torch (t) + Battery (b) = 2.50

t+b=2.50

b+1.50+b=2.50

2b=1

b=.5

Battery costs .50 and torch costs 1.50 more = 2.00

Battery = .50

Torch = 2.00

.50 + 2.00 = 2.50 = true

Total price is 2.50- torch price is 2

200/250- divide both by 50=

200/50 / 250/ 50=

4/5

5 0

3 years ago

Suppose that 30% of the applicants for a certain industrial job possess advanced training in computer programming. Applicants ar

Charra [1.4K]

Answer:

Step-by-step explanation:

From the given information:

Assume X represents the no. interviewed until 1 has advanced training.

X obeys a Geometric distribution with parameter 0.3.

X $\sim$ Geom (0.30)

For geometric distribution, the probability density is:

$P(X =x) = p(1-p) ^{x-1} \ \ \ where; x =1,2,3...$

TO calculate the required probability;

$P(X =5) =0.30 (1-0.30)^{5-1}$

$P(X =5) =0.30 (0.70)^{4}$

$P(X=5) = 0.30 \times 0.2401$

$\mathbf{P(X=5) = 0.07203}$

(b)

The expected no. of applicants that need to be interviewed are:

$E(X)=\dfrac{1}{p}$

$E(X)=\dfrac{1}{0.30}$

E(X) = 3.33

(c)

The mean and the variance can be computed as:

$E(Y) = \dfrac{1}{p}$

$E(Y) = \dfrac{1}{0.30}$

E(Y) = 3.33

$V(Y)=\dfrac{1-p}{p^2}$

$V(Y)=\dfrac{1-0.3}{0.3^2}$

$V(Y)=\dfrac{0.7}{0.3^2}$

$V(Y)=7.778$

Suppose C represents the no. of the total cost and given that each interview costs $30.

Then C = 30Y

Recall that; C is constant for a random variable X

∴

E(C) = E(30Y)

E(C) = 30E(Y)

E(C) = 30*3.33

E(C) =99.9

E(C) $\simeq$ 100

V(C) = V(30Y)

V(C) = 900 V(Y)

V(C) = 900*7.778

V(C) = 7000.2

V(C) $\simeq$ 7000

5 0

3 years ago

WHATS 9 PLUS 10!!!!!!

grigory [225]

Answer:

19 Ahahhahahqhqhw or maybe 1m HAHAHA

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3 years ago

Read 2 more answers

Please help Rewrite the product as a power: x^5x^8

Nataly_w [17]

Answer:

$x^{13}$

Step-by-step explanation:

3 0

3 years ago