How many 3/4 are in two
1 answer:
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Write the vertex form of the equation and find the necessary coefficient to make it work.
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
.. y = a*(x +3)^2 -2
.. = ax^2 +6ax +9a -2
You require the y-intercept to be 7. So, for x=0, you have
.. 9a -2 = 7
.. 9a = 9
.. a = 1
The equation you seek is
.. y = x^2 +6x +7
9514 1404 393
Answer:
42 cm²
Step-by-step explanation:
The attachment shows a couple of ways the figure can be considered.
a) Left and Right rectangles that are 5 cm high and 3 cm wide, together with a central rectangle that is 3 cm high and 4 cm wide. Then the total area is ...
5×3 + 3×4 + 5×3 = 15 + 12 + 15 = 42 . . . . cm²
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b) An enclosing rectangle that is 5 cm high and 10 cm wide with a cut-out that is 2 cm high and 4 cm wide. Then the total area is ...
5×10 -2×4 = 50 -8 = 42 . . . . cm²
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The area of the irregular figure is 42 cm².
