How many 3/4 are in two

1 answer:

5 0

How many three-fourths are in 2? 2 complete sets of three-fourths can be made and 2 of the 3 pieces need to make \frac34 are left over, so we have another \frac23 of a three-fourths. and we can see that there are 2 wholes with 4 fourths in each whole, so there are 2\times 4 fourths in 2.

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What is an equation of the line that passes through the points (-6, -5) and (-3,0)? Put your answer in fully reduced form.

MrMuchimi

Answer:

y = 5/3x +5

Step-by-step explanation:

The two-point form of the equation of a line is useful here.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (0 -(-5))/(-3 -(-6))(x -(-6)) -5

y = 5/3(x +6) -5

y = 5/3x +5 . . . . slope-intercept form

5x -3y = -15 . . . .standard form

_____

There is no "fully reduced" form of the equation of a line. There are slope-intercept form, point-slope form, two-point form, standard form, general form, intercept form, and some others. We assume that "fully reduced" applies to any fractions in the equation. The "slope-intercept" form has a fraction, so perhaps that's the form that is required.

6 0

2 years ago

Could i have some really really quick help?

nata0808 [166]

Answer:

1125 m

Step-by-step explanation:

Given equation:

$h=-5t^2+150t$

where:

h = height (in metres)
t = time (in seconds)

<u>Method 1</u>

Rewrite the equation in vertex form by completing the square:

$h=-5t^2+150t$

$\implies h=-5t^2+150t-1125+1125$

$\implies h=-5(t^2-30t+225)+1125$

$\implies h=-5(t-15)^2+1125$

The vertex (15, 1125) is the turning point of the parabola (minimum or maximum point). As the leading coefficient of the given equation is negative, the parabola opens downward, and so vertex is the maximum point. Therefore, the maximum height is the y-value of the vertex: 1125 metres.

<u>Method 2</u>

Differentiate the function:

$\implies \dfrac{dh}{dt}=-10t+150$