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3 years ago

A quadratic equation has exactly one real number solution. Which is the value of its discriminant?

1 answer:

4 0

Exactly one solution means the quadratic is a perfect square, so the usual two solutions coincide. When we have repeated roots that means the discriminant is zero.

Answer: 0

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At the Sunnyvale Playhouse, the price for an adult ticket is $12 and the price of a child's ticket is $6. For Saturday night's p

Leviafan [203]

Answer: the answer is 1.499495

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3 years ago

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HELP PLEASE

Jet001 [13]

Answer:

c $11,751

Step-by-step explanation:

The function that models Alicia's car is

$f(x) = 21000(0.93)^{x}$

where x represents the number of years since she purchased the car.

We want to find the value of Alicia's car after 8 years.

We substitute x=8 into the formula to get:

$f(8) = 21000(0.93)^{8}$

$f(8) = 21000(0.5596)$

$f(8) = 11751.218$

We round to the nearest dollar to get:

$f(8) =11751$

The correct answer is C.

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3 years ago

Compare these data sets. The equation of the trend line is listed below each data set.

Luda [366]

Answer:

b and e

Step-by-step explanation:

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3 years ago

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Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).