Answer: The percentage of hotels in the city have a nightly cost of more than $200 is 21%
Step-by-step explanation:
Since the nightly cost of hotels in a certain city is normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the nightly cost of hotels.
µ = mean cost
σ = standard deviation
From the information given,
µ = $180.45
σ = $24.02
The probability that a hotel in the city has a nightly cost of more than $200 is expressed as
P(x > 200) = 1 - P(x ≤ 200)
For x = 200,
z = (200 - 180.45)/24.02 = 0.81
Looking at the normal distribution table, the probability corresponding to the z score is 0.79
Therefore,
P(x > 200) = 1 - 0.79 = 0.21
The percentage of hotels in the city have a nightly cost of more than $200 is
0.21 × 100 = 21%
Y = 20 because both sides equal 25
180-50= 130
130-70=60
60/3= 20
Answer: In 2005 the amount spend on internet ads = $74.6 billions.
In 2009 spending on internet search ads will reach $102 billion .
Step-by-step explanation:
Given : The number of internet paid search ads is increasing as advertisers move away from traditional marketing methods.
The equation
can be used to project spending on internet search ads, in billions of dollars, x years after 2000.
To estimate spending on internet ads in 2005.
We need to put x= 5 in the above equation [∵2005-2000=5]



i.e. In 2005 the amount spend on internet ads = $74.6 billions.
Put y= 102 in the given equation, we get

[Subtract 40.1 from both sides]
And 2000+9=2009 [x is the number of years after 2000]
Hence, in 2009 spending on internet search ads will reach $102 billion .
The answer to the question
Here is the answer :
people who like both the songs is 35 and
people who like only folk songs is 100.