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Tems11 [23]
4 years ago
12

PRE CALC PLEASE HELP!!!

Mathematics
1 answer:
Diano4ka-milaya [45]4 years ago
6 0

Answer: \bold{\pm \{1, 2, 3, 4, 6, 12, \dfrac{1}{2}, \dfrac{3}{2}\}}

<u>Step-by-step explanation:</u>

        Q                       P

f(x) = 2x³ - bx² + cx + 12

Possible rational roots are all of the factors of P divided by all of the factors of Q, including both positive and negative signs.

\quad \pm \dfrac{\text{factors of P}}{\text{factors of Q}}\\\\=\pm \dfrac{\text{factors of 12}}{\text{factors of 2}}\\\\=\pm \dfrac{1,2,3,4,6,12}{1,2}\\\\=\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \dfrac{1}{2}, \pm \dfrac{3}{2}\\

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6. Check whether - 150 is a term of the AP: 11, 8,5,2...
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