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Zigmanuir [339]
3 years ago
15

Find DE. A.4 B.5/3 C.7 D.11

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

DE = 11

Step-by-step explanation:

DE = x + 7

EF = 7

DF = 4x + 2

DF = DE + EF (segment addition postulate)

Substitute

4x + 2 = x + 7 + 7

4x + 2 = x + 14

Collect like terms

4x - x = -2 + 14

3x = 12

Divide both sides by 3

x = 12/3

x = 4

✔️DE = x + 7

Plug in the value of x

DE = 4 + 7

DE = 11

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∠1 and ∠2 are a linear pair. m∠1 = x - 29, and m∠2 = x + 61. Find the measure of each angle. A) ∠1 = 74; ∠2 = 106 B) ∠1 = 74; ∠2
Ne4ueva [31]

Answer:

D)

Step-by-step explanation:

∠1 + ∠2 = 180 {linear pair}

x - 29 + x + 61 = 180   {add the like terms}

2x + 32 = 180   {subtract 32 from both sides}

2x + 32 - 32 = 180 - 32

2x = 148

x = 148/2

x = 74

∠1 = x - 29 = 74 - 29 = 45

∠2 = x + 61 = 74 + 61 = 135

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4 years ago
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Which is the equation of a trend line that passes through the points (3,95) and (11,12)
Vladimir [108]

Answer:

y-95=-83/8(x-3)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(12-95)/(11-3)

m=-83/8

y-95=-83/8(x-3)

3 0
4 years ago
Solve the equation. Check the solution. <br> a - 3.2 = 5.5
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the correct answer is 8.7

6 0
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Complete computefibonacci() to return fn, where f0 is 0, f1 is 1, f2 is 1, f3 is 2, f4 is 3, and continuing: fn is fn-1 + fn-2.
anastassius [24]

Answer:

Fibonacci series is given by

f(0)=0, f(1)=1, f(2)=1, f(3)=2, f(4)=3.....

As you can see using the above result

f(4)=f(3) + f(2),

f(3)=f(2) + f(1),

f(2)=f(1) + f(0)

Proceeding using same pattern

f(5)=f(4) + f(3)=3+2=5

f(6)=f(4) + f(5)=3+5=8

f(7)=f(6) + f(5)=8+5=13

f(8)=f(7) + f(6)=13+8=21

f(9)=f(8) + f(7)= 21+13=34

f(10)=f(9) + f(8)=34+21=55

...........................................

..........................................

f(n-2)=f(n-3)  + f(n-4)

f(n-1)=f(n-2)+ f(n-3)

Similarly and finally we get using the same pattern we get, As given f(n)=f(n-1) + f(n-2).




3 0
4 years ago
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