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Naddika [18.5K]
3 years ago
13

Solve the equation. Check the solution. a - 3.2 = 5.5

Mathematics
2 answers:
forsale [732]3 years ago
8 0

Answer:

8.7

Step-by-step explanation:

one way that works the best, since you have your unknown variable ( a ), you will have to move -3.2 over to the side where 5.5 is. after you do that, you have to add together the 3.2 and the 5.5 because whenever you do something like that, you have to do the opposite of that. hope that made sense!

Delicious77 [7]3 years ago
6 0

Answer:

the correct answer is 8.7

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Diego is thinking of two positive numbers. He says, 'If we triple the first number and double the second number, the sum is 34.'
UNO [17]

1st number: 0

2nd number: 17

Answer

Step-by-step explanation:

3x+2y=34 x is the first number, y is the second.

1/2x+2y=34 multiply each number by two to get rid of the integer by the variable x.

x+4y=68 solve for x.

x=68-4y add this into the first equation to solve for variable y.

3(68-4y)+2y=34 solve for y.

204-10y=34

-10y= -170

y=17

now to solve for x

x= 68-4(17)

x= 0

8 0
3 years ago
A and b are positive integers and a-b=2. Evaluate the following:<br> 9^1/2b/3^a
OlgaM077 [116]

Answer:

\frac{1}{ 9 }

Step-by-step explanation:

\huge \frac{ {9}^{ \frac{1}{2}b } }{ {3}^{a} }  \\  \\  =  \huge \frac{ {( {3}^{2} )}^{ \frac{1}{2}b } }{ {3}^{a} } \\  \\  =  \huge \frac{ { {3}}^{2 \times  \frac{1}{2}b } }{ {3}^{a} }  \\  \\  \huge =  \frac{ {3}^{b} }{ {3}^{a} }  \\  \\  \huge =  \frac{1}{ {3}^{a - b} }  \\  \\   \huge=  \frac{1}{ {3}^{2} } \\  ( \because \: a - b = 2)\\  \\  \huge =  \frac{1}{ 9 }

5 0
3 years ago
What numbers multiply to give 100 and when summed up give 25................................​
Kruka [31]
It’s 3 times 25 plus 74
7 0
3 years ago
List of fractions and decimals in order from least to greatest 3/4, -7/10, -3/4, 8/10
Archy [21]
-3/4,-7/10,3/4,8/10
4 0
3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

Learn more about amount here:

brainly.com/question/4567186

#SPJ1

6 0
2 years ago
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