Answer:
12.1
Step-by-step explanation:
We use the formula for the distance between two arbitrary points 
and 
in the xy-coordinate plane, that is:
So, replacing the points 
and 
, we obtain:
that is the answer.
note: observe that we only use the coordinates between the two midpoints and not the point J.
You might want to check what I did just in case cause it's been a few years but it should be good. I hope this helps!
10.75 x 8.5 = 91.375
Answer: x = 50
Step-by-step explanation:
-0.2(x - 20) = 44 - x
-0.2x + 4 = 44 - x (distribute the -0.2)
+ x + x
-----------------------------------------------------
0.8x + 4 = 44
- 4 - 4
-------------------------------------------------------
0.8x = 40 (divide by 0.8)
x = 50
Answer:
g(-3) = -13
Step-by-step explanation:
Plug in -3 for n in the equation:
g(n) = 3n - 4
g(-3) = 3(-3) - 4
Remember to follow PEMDAS. First, multiply, then subtract:
g(-3) = 3 * -3 = -9
g(-3) = -9 - 4
g(-3) = -13
-13 is your answer for g(-3).
~
Answer:
![3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }](https://tex.z-dn.net/?f=3%20%2B%20%5Cfrac%7B1%7D%7B2%5Csqrt%7B3%7D%20%7D%20%2B%20%5Cfrac%7B1%7D%7B5%5Csqrt%5B5%5D%7B81%7D%20%7D)
Step-by-step explanation:
Just to make it easier to see, 
and ![\sqrt[5]{x} = x^{\frac{1}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D)
This way we could more easily use the power rule of derivatives.
So if f(x) = 
then f'(x) will be as follows.
f'(x) = ![x^{1} +\frac{1}{2} x^{-\frac{1}{2} } +\frac{1}{5} x^{-\frac{4}{5} } = x +\frac{1}{2x^{\frac{1}{2} }} +\frac{1}{ 5x^{\frac{4}{5} }} = x +\frac{1}{2\sqrt{x}} +\frac{1}{ 5\sqrt[5]{x^4} }](https://tex.z-dn.net/?f=x%5E%7B1%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20x%5E%7B-%5Cfrac%7B1%7D%7B2%7D%20%7D%20%2B%5Cfrac%7B1%7D%7B5%7D%20x%5E%7B-%5Cfrac%7B4%7D%7B5%7D%20%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2x%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205x%5E%7B%5Cfrac%7B4%7D%7B5%7D%20%7D%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205%5Csqrt%5B5%5D%7Bx%5E4%7D%20%7D)
to find f'(3) just plug 3 into f'(x) so
