Answer:
The person who has the greatest spread is Jezebal because his range is 22 while Collin's range is 18.
Jezebal's range :
26 - 4 =22
Collin's range:
21 - 3 = 18
The person who has the least IQR is Collin
Jezebal :
4, 5, 8, 10, 11, 14, 20, 20, 26
Since there are nine values 11 is the median so the first quartile is 6.5 and the third quartile is 20. 20 - 6 = 14
Collin : 3, 9, 9, 14, 15, 16, 17, 20, 21
The median is 15, the first quartile is 9 and the third quartile is 18.5. 18.5 - 9 = 9.5
Jezebal has the greatest spread
Collin has the least IQR
Do you do K12 by any chance?
Point A: 60
Point B: 60
Point C: 50
Point D: 50
The distance a point is from the y axis is the absolute value of the x-coordinate, because the x-coordinate is how far (and the direction) to go from the y axis. However, because it also takes into account the direction, we have to find the absolute value of it (so it is positive), since distance has to be positive.
Assume the sum is 100. The ratio of the two numbers is 15:10. This means that we can divide this indow 15+10, or 25 parts. Let us do that. Divide 100 into 25 parts and see how much is in each part. 100/25 is 4, meaning that there is 4 in each part. 15 parts will have 15*4, or 60. 10 parts will have 10*4, or 40. To confirm, add 40 and 60. It matches with what we started out with, 100.
The two numbers, assuming the sum is 100, are 40 and 60. 60 is the greater value.
I believe if I did this correctly, it should be 4 2/7, hope this helps!
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
