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3 years ago

Need help with this question ! :(

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

Answer:

Step-by-step explanation:

mash [69]3 years ago

6 0

Answer:

-4

Step-by-step explanation:

2x + 3y = -14

x - y = 3

Multiply the second equation by -2 to eliminate x

2x + 3y = -14

-2x +2 y = -6

-----------------------

5y = -20

Divide by 5

5y/5 = -20/5

y = -4

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The equation 6x2 - 132 +5 -0 has solutions of the form

MArishka [77]

Answer:

(A)

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B)

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Step-by-step explanation:

The given equation is

$6x^2 - 13x + 5 = 0$

The solution is of the form as given by

$x=\frac{N\pm\sqrt{D}}{M}$

(A) Use the quadratic formula to solve this equation and find the appropriate integer values of N, M and D. Do not worry about simplifying the VD yet in this part of the problem.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The equations of N, M and D are

$N = -b$

$D =b^2 -4ac$

$M = 2a$

The values of a, b and c are

$a = 6 \\\\b = -13 \\\\c = 5$

So,

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2-3/4

N = 13

D = 49

M = 12

$x=\frac{13\pm\sqrt{49}}{12}$

$x=\frac{13\pm7}{12}$

$x=\frac{13+7}{12}$ and $x=\frac{13-7}{12}$

$x=\frac{20}{12}$ and $x=\frac{6}{12}$

$x=\frac{5}{3}$ and $x=\frac{1}{2}$

$x = (\frac{5}{3} , \: \frac{1}{2})$

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