3 years ago

Please help me with this

Mathematics

1 answer:

alekssr [168]3 years ago

3 0

Answer: $30^{\circ}$

Step-by-step explanation:

Given

$\sin 60=\dfrac{\sqrt{3}}{2}$

For

$\cos \theta =\dfrac{\sqrt{3}}{2}$

It indicates $\theta$ lies in I st quadrant. The value of cosine $30^{\circ}$ is equal to $\dfrac{\sqrt{3}}{2}$

Therefore, $\theta$ must be $30^{\circ}$

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