Complete question :
Bernie and Chloe hiked the Tremont Trail to the end and back. Then they hiked the Wildflower trail to the end before stopping to eat lunch. Before Ricardo ate his lunch, he hiked 2 2/3 times as far as Bernie and Chloe. How far did he hike?
Required diagram is attached below
Answer:
25 miles
Step-by-step explanation:
Tremont Trail = 3 1/2 miles
Wildflower trail = 2 3/8 miles
Distance covered ; Tremont Trail and back : (3 1/2 * 2). = 7/2 * 2 = 14 /2 = 7 miles
Total distance covered by Bernie and Chloe before stopping for lunch /
(7 miles + 2 3/8 Miles) = 9 3/8 miles = 75/8 miles
Ricardo's distance = 2 2/3 * Bernie and Chloe's total distance
Ricardo's distance = 8/3 * 75/8 = 600 /24 = 25 miles
Answer: Write something greater than 5 at the ones place or the tenths place or having digits that are greater than 0 after the 5 in the tenths place.
Step-by-step explanation:
You can try to show this by induction:
• According to the given closed form, we have
, which agrees with the initial value <em>S</em>₁ = 1.
• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

and

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

From the given recurrence, we know

so that






which is what we needed. QED
Yeah i cant see them either