So first what you want to do is find out how much closer they would be after one hour. Since they're both moving towards each other, that means they gain,
14 + 16 = 30 m in one hour.
(because they're both moving towards each other, so for the amount they get closer to each other, you want to add both of their speeds)
Since they were originally 180 miles apart, and you want to find how long it would take for them to be 20 miles apart, you want to just subtract 20 from 180 to find the total distance they have to travel.
180 - 20 = 160
Now divide 160 by 30 to find out how many sets of 30 miles, or one hour time periods, there are in 160 miles.
160 / 30 = 16/3 hours.
To make this into minutes, you can just multiply by 60.
16/3 * 60 = 960/3
960/3 = 320
So it'll be 320 minutes before they are 20 miles apart.
Keeping in mind that, there are 5280 feet in 1 mile, and 60 minutes in an hour and 60 seconds in each minute, thus 60*60 seconds in an hour, or 3600 seconds.
Hi, I’ll gladly be happy to help, but could you type out the problem instead because the photo is too blurry for me to see.
Answer:
No, it is D.
Step-by-step explanation:
<em>It can not be A or C, because length can not be negative</em>
Because the y is the same, you only have to <em>count the distance of the x-axises</em>.
4 - (-3) is 7 units, which is D.
Answer:
The constant of variation is 5.
Step-by-step explanation:
In direct variation, as y varies directly with x, the standard equation is
y = kx,
where k is the constant of variation.
In your case, we use R and S. R varies directly with S, so we have
R = kS
We know that when S = 16, R is 80, so we plug in those values and solve for k, the constant of variation.
R = kS
80 = k(16)
k = 80/16
k = 5
