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bulgar [2K]
3 years ago
8

What is the integer?

Mathematics
1 answer:
wel3 years ago
3 0

Answer:

-40

Step-by-step explanation:

This is because she LOST 40 dimes making it a negative number, so the integer to represent this would be -40.

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Ellis is painting wooden fenceposts before putti by then in his yard. They are each 5 feet tall and have a diameter of 1 foot. T
lawyer [7]

Answer:

39.25

Step-by-step explanation:

diameter. is 1 therefore radius is 1/2

formula is πr²h

where

h is height=5

=3.14x½²x5

=3.925 for one paint

therefore for 10 paints, we have

=3.925x10

=39.25

3 0
2 years ago
Collin did the work to see if 10 is a solution to the equation r/4=2.5
Natasha2012 [34]

Answer:

Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.

Step-by-step explanation:

\frac{r}{4}  = 2.5 \\ lhs =  \frac{r}{4}  \\  =  \frac{10}{4}  \\  = 2.5 \\  = rhs \\  \therefore \:  \frac{r}{4}  = 2.5 \\

3 0
3 years ago
What is the final price of a $30 item at 20% off and then %20 added?
stiv31 [10]
$30 because you are taking away 20% of $30 and then adding back that 20%.
3 0
3 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
0.33 as a fraction in simplest form
vichka [17]
0.33 = 33/100.

It cannot be reduced after that.
4 0
3 years ago
Read 2 more answers
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