6/16 which is .375, round that to the nearest hundredth and you get .38
We can divide arrow in two sections:
A 1 ( rectangle ) = 4 x 5 = 20 sq in.
A 2 ( triangle ) = ( 6 x 3 ) / 2 = 9 sq in.
A = A 1 + A 2 = 20 + 9 = 29 sq in
Answer: B )29 sq in.
Answer:
a=8
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 +b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 +15^2 = 17^2
a^2 +225 = 289
Subtract 225 from each side
a^2 +225-225=289-225
a^2 = 64
Take the square root of each side
sqrt(a^2) = sqrt(64)
a = 8
Answer:
The width of the frame is 3 inches
Step-by-step explanation:
We are told that the inner rectangle is 10 inches by 16 inches.
It means the outer rectangle has to be (L = 10 + 2x) by (W = 16 + 2x),
Where x represents the width of the frame.
The perimeter of the frame is given by; p = 2L + 2W
p = 2(10+2x) + 2(16+2x)
We are given perimeter, P = 76
Thus;
2(10 + 2x) + 2(16 + 2x) = 76
Divide both sides by 2 to give;
(10+2x) + (16+2x) = 38
(10+16) + (2x+2x) = 38
4x = 38 - 26
4x = 12
x = 12/4 = 3
The width of the frame is x = 3 inches
