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3 years ago

12

Given that cot(θ)= -√5/3 and cos(θ) < 0, find sin(θ)

1 answer:

anyanavicka [17]3 years ago

7 0

D. 3√14 /14

Step-by-step explanation:

given that cot(θ)= -√5/3 and cos(θ) < 0

cot(θ)= -√5/3 and cos(θ) < 0, the angle should be on quadrant II.

cot(θ)= -√5/3 => x = -√5 , y = 3

h = √(-3)²+5 =√14

so, sin(θ) = y/h = 3/√14 = 3√14 /14

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Full working out for this question please

kvv77 [185]

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Step-by-step explanation:

<u>Based on the fact:</u>

$tan(x)=\frac{opposite}{adjacent}$

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$\\\\tan(29)=\frac{t}{9.6} \\\\t=9.6*tan(29)$

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3 years ago

Lauren bring treats next to class one day she gives 3/5 of them to her friends Gareth Tammy and Camilla if she gave them 21 frui

Salsk061 [2.6K]

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3 years ago

What is the solution to -1.6 > b - (-4.4)

Inessa05 [86]

$\\ \sf\longmapsto -1.6>b-(-4.4)$

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3 years ago

Find the values of x and y.

sweet [91]

X is 90°
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6 0

3 years ago

Read 2 more answers

40 points fast For the following set of test scores, identify:

myrzilka [38]

Answer:

The measure of center would this student want his teacher to use is the

median $= {\bf 75}$

Mean $= {\bf 5}$ , Mode $={\bf 82}$ , Range $={\bf40}$ and Interquartile Range $= {\bf 32}$

Step-by-step explanation:

Given Data set $= 50,55,70,75,82,82,90$

Number of elements in data set $= 7$

To find Mean

The ‘Mean” is the average of a set of numbers.

The "Mean" is computed by adding all of the numbers in the data together and dividing by the number of elements contained in the data set.

Mean $= \frac{50 +55 +70 + 75 + 82 + 82 + 90} {7 }$

Mean $= \frac{504}{7}$

Mean $= 5$

Median

The “Median” is the middle value of a set of ordered numbers.

Therefore Median $=75$

Mode

The "Mode" for a set of data is the value that occurs most often.

It is not uncommon for a data set to have more than one mode. This happens when two or more elements occur with equal frequency in the data set.

Therefore Mode $=82$

Range

The "Range" is the difference between the largest value and smallest value in a set of data.

Range $= 90-50$

Range $= 40$

Interquartile Range

The “Interquartile Range” is the difference between smallest value and the largest value of the middle 50% of a set of data.

The "Interquartile Range" is from Q1 to Q3:

To find the interquartile range of a set of data:

The cut the list into four equal parts

. The quartiles are the “cuts”

The interquartile range is the distance between the two middle sets of data

Interquartile Range $= Q_3-Q_1$

Interquartile Range $= 82-50$

Interquartile Range $= 32$

5 0

3 years ago