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malfutka [58]
3 years ago
13

Find the equation of the line that passes through the point (3,14) and is parallel to y=2/3x -6

Mathematics
2 answers:
sammy [17]3 years ago
7 0
You use the point slope formula 
y-y1=m(x-x1)
y-14=2/3(x-3)
y-14=2/3x-2
+14      +14
y=2/3x+12
Ugo [173]3 years ago
4 0
Y=mx+b
m=slope

paralell ines have same slope
y=2/3x-6
slope is 2/3

the equation of aline that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
(3,14) and slope is 2/3
y-14=2/3(x-3)
y-14=2/3x-2
y=2/3x+12
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If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.
adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20  + 2x - 10 = 90

      2x + 60 + 6x - 30 = 270

               8x + 30 = 270

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                          x = 30

2x/3 + 20 = 60/3 + 20 = 20 + 20 = 40

2x - 10 = 2(30) - 10 = 60 - 10 = 50  or  90 - 40 = 50

       

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3 years ago
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kifflom [539]

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7 0
2 years ago
13.
Solnce55 [7]

Answer:

answer would be E. 16,000,000

Step-by-step explanation:

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just round that number and you get 16,000,000

hope this helped!!

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3 years ago
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Step-by-step explanation:

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3 years ago
how do i write an equation of a quadratic formula when given the roots and y intercept? is there a formula i can plug the number
klio [65]

9514 1404 393

Answer:

  y = -3x^2 +3x +6

Step-by-step explanation:

For roots p and q, the equation can be written as ...

  y = a(x -p)(x -q)

The value of 'a' must be determined so that the product <em>apq</em> is equal to the y-intercept. One could say that the formula is ...

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For your given values of p = 2, q = -1, y-intercept = 6, this becomes ...

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  y = -3x^2 +3x +6

7 0
3 years ago
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