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Serhud [2]
3 years ago
10

What are some examples of lab saftey rules. Explain why these rules are put in place for the learning environment and what would

a lab class look like without any lab safety rules.​
Biology
2 answers:
Andrews [41]3 years ago
7 0

Answer:

How was the government able to make children go to residential school?

help me out bro!!! !! ! !

kow [346]3 years ago
3 0
Examples of lab safety rules:
- wearing protective and proper clothing (eg. goggles, gloves, close-toed shoes)
-locating emergency equipment (eg. eyewash station, fire extinguisher, fire blanket)
- not eating or drinking liquids
- handling chemicals properly and following lab procedures
- dispose waste properly and clean up area when finished.
-do not consume any chemicals or substances
- be attentive
There’s a lot more but these are the most common ones.


—————-
These rules are put in place for the learning environment because it ensures the safety of all persons in the lab and prevents any accidents from happening such as injuries and dangers. They also prevent dangers such as cross contamination and explosions from occurring.

A class without lab safety rules would be extremely dangerous and even deadly. People would get injured and many hazardous risks would come up. (like cross contamination, explosions, mentioned above). Injuries like blindness, burns, and cuts can occur. Just imagine a class of 2nd graders with no teacher around. that’s kind of like a lab without safety rules :)

hope that helps!
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Hey there!

Here is your answer:

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Reason:

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4 years ago
You decide to conduct a genetic analysis of these mutant lines by crossing each with a pure-breeding wild-type line. The numbers
maxonik [38]

Complete question:

You will find the complete question in the attached files

Answer:

  • For the twist trait: The <em>mutant allele is dominant</em> to its corresponding wild-type allele
  • For the forked trait: the <em>mutant allele is dominant</em> to its corresponding wild-type allele
  • For the pale trait: The <em>mutant allele is neither dominant nor completely recessive</em> to its corresponding wild-type allele

Explanation:

  • Cross 1:  twisted x wild-type ----> Pure lines

Parentals)    TT   x      tt

<em>F1) twisted leaves, Tt</em>. ---> Heterozygous

Parentals) Tt    x    Tt

Punnett square)    T     t

                       T    TT   Tt

                        t    Tt    tt

<em>F2) 53 twisted, 18 wild-type </em>

Total number of individuals in the F2 = 53 + 18 = 71

71 plants -------- 100% of the F2

53 twisted------X = 75% TT + Tt

18 wild-type----X = 25% tt

<em>Phenotypic ratio 3:1</em>

The phenotype of the F1 and F2 progeny tells us that the twist trait is dominant over the wild type. The fact that the whole F1 generation was twisted is enough information to assume that the wild type is recessive and the twisted is dominant. Also, the phenotypic ratio of the F2 corroborates this assumption.

  • Cross 2: forked x wild-type ---> Pure Lines

Parentals)  FF     x     ff

F1) 100% forked, Ff----> Heterozygous

Parentals)  Ff     x     Ff

Punnett square)    F      f

                    F       FF    Ff

                    f        Ff     ff

F2) 49 forked and 16 wild-type plants

Total number of individuals in the F2 = 49 + 16 = 65

65 plants -------- 100% of the F2

49 forked------X = 75% FF + Ff

16 wild-type----X = 25% ff

<em>Phenotypic ratio 3:1</em>

The phenotype of the F1 and F2 progeny tells us that the twist trait is dominant over the wild type. The fact that the whole F1 generation was forked is enough information to assume that the wild type is recessive and the forked is dominant. Also, the phenotypic ratio of the F2 corroborates this assumption.

  • Cross 3: pale x wild-type ---> Pure lines

Parentals) PP    x    pp

F1) 100% Pp, intermediate color.

Parentals) Pp   x   Pp

Punnett square)   P       p

                      P    PP    Pp

                       p    Pp    pp

F2) 34 intermediate, 17 wild-types, and 16 pale.

Total number of individuals in the F2 = 34 + 17  + 16 = 67

67 plants -------------- 100% of the F2

34 intermediate ------X = 51% Pp

17 wild-type-------------X = 25% pp

16 pale -------------------X = 24% PP

<em>Phenotypic ratio 1:2:1</em>

The phenotype of the F1 and F2 progeny tells us that the pale trait is not dominant neither recessive to the wild type. The fact that the whole F1 generation was intermediate is enough information to assume that none of the traits dominates over the other. This is a case of incomplete dominance.  The heterozygous individual express an intermediate phenotype between both the parentals´ one. Also, the phenotypic ratio of the F2 corroborates this assumption.  

Download pdf
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