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VARVARA [1.3K]
3 years ago
12

Does anyone know what the answer?

Mathematics
2 answers:
11111nata11111 [884]3 years ago
5 0

Answer:

x = 7

Step-by-step explanation:

Hi,

7x - 7 = 4x + 14

3x - 7 = 14

3x = 21

x = 7

I hope this helps :)

anzhelika [568]3 years ago
5 0

Answer: x = 7

Step-by-step explanation:

7x - 7 = 4x + 14

    3x = 21

       x = 7

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The sum of two numbers is 100, the difference between the two numbers is 26. What is the number that is less?
Zepler [3.9K]
The numbers that would be smaller would be the two with the difference of 26.
27-1=26 where as, if you were to use a 1 in each, 99+1= 100. Therefore 27 and 1 (28) is less than 99 and 1 (100).

6 0
3 years ago
What is the value of x when f(x)=7? the function or whatever is f (x) =x^3 - 1
pashok25 [27]

Answer:

f ( 7 ) = 342  

Step-by-step explanation:

Step 1:

f ( x ) = x³  - 1          Function

Step 2:

f ( 7 ) = 7³ - 1        Input x value

Step 3:

f ( 7 ) = 343 - 1        Exponents

Answer:

f ( 7 ) = 342          Subtract

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
What is a four digit whole number that is divisble by 2​
valentinak56 [21]

Answer:

any even number is divisible by 2.  

Here's an example:  2222

There are lots of others as well.

3 0
3 years ago
Read 2 more answers
the functions f and g are defined as follows f(x)=-5x+2 g(x)=3x^2-3x find f(g) and g(-2) simplify your answer as much as possibl
daser333 [38]

Answer:

f(g) = -15x^2 + 15x + 2.

g(-2) = 18.

Step-by-step explanation:

f(g) = -5(3x^2 - 3x) + 2

= -15x^2 + 15x + 2.

g(-2) = 3(-2)^2 - 3(-2)

= 12 + 6

= 18.

8 0
3 years ago
Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
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