Answer:
f(x) > 0 over the interval 
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from
, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from
to -3, since between the values -4 and -3 the function adopts negative values.
-3x-2-6x=-4-<em>(-4x)</em>+12
-9x-2=-16x+12
7x=14
x=2.
You probably got confused with the italicized part.
Answer:
Your question is in what base please?
I think it may be the ability to get the correct/same answer (percision) to within 40 feet.
Answer:
a
Step-by-step explanation: