PLZ HELP ME IM GOING TO FAIL THEN PLZ A cyclist cycles a distance of 48 miles in a time of 3 hours.

Mathematics

2 answers:

Pani-rosa [81]3 years ago

8 0

Answer:

her average speed is 16 miles per hour

Step-by-step explanation:

do 48 divided by 3 = 16

Mrrafil [7]3 years ago

7 0

Answer:

16miles per hour

Step-by-step explanation:

your total number of miles being 48 and your number of hours being 3 you want to get your answer to be the number of miles in one hour or per hour so you would devide your miles by the number of hours

48/3 = 16 miles per hour

You might be interested in

Choose the inverse of y=X2-2

pickupchik [31]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Question is in the image, thank you

Alex787 [66]

sin H = Opposite / Hypotenuse

sin H = 5/13

sin H = 0.384615

<H = 22.6198

<H = 23 (nearest degree)

Answer is first one.

6 0

3 years ago

1. Approximate the given quantity using a Taylor polynomial with n3.

Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

$f(x) = x^{1/4}$

The n-th order Taylor polynomial for function f with its center at a is:

$p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}$

As n = 3 So,

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}$

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}$

$p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} } (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} + (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}$

$p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} } (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} + (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}$