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3 years ago

What are the steps to finding the line of symmetry from an equation?

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

Turn it into y=mx+b form (slope-intercept form)

Step-by-step explanation:

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Somebody help me ASAP

xeze [42]

Answer:

10.5

Step-by-step explanation:

14/4 = 3.5

7/2 = 3.5

N/3 = 3.5

N = 10.5

Pls mark Brainiest :)

8 0

3 years ago

PLEASE HELP IM STUCK WITH THIS ONE AND I DONT KNOW :(

labwork [276]

The line crossing the two parallel lines forms an allied angle
So using the theory “allied angles add up to 180 degrees” we can find x

76 + x =180
x= 180-76
x=104 (Option B)

6 0

2 years ago

Help me plz math (picture)

skad [1K]

For 34, since each diameter is in scientific notation , meaning that we have one number (1-9) followed by a decimal, we simply see which has the smallest power, which is cell C.

For 35, we multiply them out to get 0.83*10^2 (we subtract exponents when dividing). Since scientific notation is one integer from 1-9 followed by a decimal, we move 0.83 one place to the right and therefore remove one power from 10^2, getting 8.3*10

6 0

2 years ago

What is the measure of angle W in the figure

Angelina_Jolie [31]

Angle w equals 130 degrees.

Explanation:
A line equals: 180 degrees total.
180-50=130

6 0

2 years ago

Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

8 0

1 year ago