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dybincka [34]
3 years ago
13

Una bañera en forma de trapecio tiene un area de 60 metro ademas se sabe que su base mayor es 3/2 mas grande que su base menor c

alcule la altura cuando la base menor es 18 metros
Mathematics
1 answer:
valkas [14]3 years ago
4 0

Respuesta:

3,2 metros

Explicación paso a paso:

Área del trapecio:

A = 1/2 (a + b) h

h = altura; ayb son las bases

Área, A = 60

Sea una base más pequeña = a = 18;

b = 18 + 3/2 = 19,5

La altura se puede calcular así;

60 = 1/2 (18 + 19,5) h

60 * 2 = 37,5 horas

120 = 37,5 h

h = 120 / 37,5

h = 3,2 metros

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Answer:

Two triangles are similar if and only if the corresponding sides are in proportion and the corresponding angles are congruent. To show two triangles are similar, it is sufficient to show that two angles of one triangle are congruent (equal) to two angles of the other triangle.

Step-by-step explanation:

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3 years ago
What is the sum of the infinite geometric series 9−6+4−83+...9-6+4-83+...??
vivado [14]
Successive terms have a common factor of -\dfrac23, which means the nth partial sum of the series can be written as

S_n=9-6+4-\dfrac83+\cdots+9\left(-\dfrac23\right)^{n-1}
S_n=9\left(1+\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\cdots+\left(-\dfrac23\right)^{n-1}

\implies-\dfrac23S_n=9\left(\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\left(-\dfrac23\right)^4+\cdots+\left(-\dfrac23\right)^n\right)

\implies S_n-\left(-\dfrac23\right)S_n=9\left(1-\left(-\dfrac23\right)^n\right)
\dfrac53S_n=9\left(1-\left(-\dfrac23\right)^n\right)
S_n=\dfrac{27}5\left(1-\left(-\dfrac23\right)^n\right)

As n\to\infty, the geometric term vanishes, leaving you with

S=\displaystyle\lim_{n\to\infty}S_n=\dfrac{27}5
7 0
3 years ago
Anyone up that can help me ​
LekaFEV [45]

Answer:

Step-by-step explanation:

reflection

3 0
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Step-by-step explanation:

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Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
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