75√109.5=1.46
1.2√79.1=65.92
5.2√9.16=1.76
17.1 =17.1
Answer:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:

The best answer for this case would be:
C. Poisson distribution
Step-by-step explanation:
Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is
The probability mass function for the random variable is given by:
And f(x)=0 for other case.
For this distribution the expected value is the same parameter
And for this case we want to calculate this probability:

The best answer for this case would be:
C. Poisson distribution
Answer:
B
Step-by-step explanation:
1.6/0.2=8
10⁵-10²=10³