Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
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<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
Answer:
The indifference point is 500 calls.
Step-by-step explanation:
Giving the following information:
Plan 1 charges $32 per month for unlimited calls and Plan 2 charges $17 per month plus $0.03 per call.
I assume we have to determine the indifference point between the two plans.
<u>First, we need to structure the cost formulas:</u>
Plan 1= 32
Plan 2= 17 + 0.03*x
x= call
<u>Now, we need to equal both formulas:</u>
32 = 17 + 0.03x
15= 0.03x
500= x
The indifference point is 500 calls.
Plan 1= $32
Plan 2= 17 + 0.03*500= $32
Answer:
no
Step-by-step explanation:
He reads 2 pages per minute. So Divide 2 hours in it's minute form by 240. So like this:
240÷120=2