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Novosadov [1.4K]
3 years ago
11

Problem 10-9 A sample of 40 observations is taken from a population of unknown mean wherein the standard deviation is assumed to

be 5 grams. The computed value of the sample mean is 38.0 grams. Construct confidence intervals for each of the following levels of confidence: (a) 90% Confidence Interval
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer: (36.7, 39.3)

Step-by-step explanation:

Confidence interval for population mean:

\overline{x}\pm z^c\dfrac{\sigma}{\sqrt{n}} , where n= sample size, \overline{x}= sample mean, \sigma = population standard deviation, z^c = critical z value.

Given: n= 40 , \sigma=5\ g,\ \ \ \overline{x} = 38.0\ g

Critical z-value for 90% confidence = 1.645

Then, required confidence interval:

38.0\pm(1.645)\dfrac{5}{\sqrt{40}}\\\\= 38.0\pm (1.645)(0.79057)\\\\\approx38.0\pm1.30\\\\= (38-1.30,\ 38+1.30)=(36.7,\ 39.3)

Hence, a 90% Confidence Interval =  (36.7, 39.3)

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Why the product (−5)(−4) must be equal to 20.
KengaRu [80]

Answer:

Multiplying to negative numbers equals a positive answer.

Step-by-step explanation:

7 0
2 years ago
3/38-3/7<br> 2+1/35<br> 3/56+3/2
prohojiy [21]

Answer:

87/56

Step-by-step explanation:

Simplify the following:

3/56 + 3/2

Put 3/56 + 3/2 over the common denominator 56. 3/56 + 3/2 = 3/56 + (28×3)/56:

3/56 + (28×3)/56

28×3 = 84:

3/56 + 84/56

3/56 + 84/56 = (3 + 84)/56:

(3 + 84)/56

3 + 84 = 87:

Answer:  87/56

4 0
3 years ago
used books cost $2.27 each. which represents the total number of books that can be purchased for $10?
siniylev [52]

Answer:

4 books

Step-by-step explanation:

The cost for one used = $2.27

The question requires you to find the number of books that could be purchased with $10

Let assume the cost for a single used book to be $ t

If you have $ x in your pocket then the number of books you can purchase with $ x will be;

number of books= $ x/ $t.............................(a)

Applying this expression to the question;

$t= $2.27

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4 0
2 years ago
Read 2 more answers
The function h(t)=-4.92t^2+17.69t+575 is used to model an object being tossed from a tall building, where h(t) is the height in
nikklg [1K]
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575

</span> For the domain we have:
<span> </span>We match zero:
 -4.92t ^ 2 + 17.69t + 575 = 0
 We look for the roots:
 t1 = -9.16
 t2 = 12.76
 We are left with the positive root, so the domain is:
 [0, 12.76]

 For the range we have:
 We derive the function:
 h '(t) = - 9.84t + 17.69
 We equal zero and clear t:
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 t = 17.69 / 9.84
 t = 1.80
 We evaluate the time in which it reaches the maximum height in the function:
 h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
 h (1.80) = 590.90
 Therefore, the range is given by:
 [0, 590.9]

 Answer:
 the domain and range are:
 
domain: [0, 12.76] range: [0, 590.9]
5 0
3 years ago
Read 2 more answers
Dont be wrong got 2 more
valina [46]
Use the given formula
C = 2(pi)r
Given pi = 3.14, r = 4
C = 2(3.14)(4) = 25.12 inches

Solution: 25.12 inches
8 0
2 years ago
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