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Dima020 [189]
3 years ago
14

andrea drove 200 miles using 9 gallons of gas. At this rate, how many gallons of gas would she need to drive 420 miles?

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Given : Andre drove 200 Miles using 9 Gallons of Gas

⇒ Andre drives 1 Mile using [\frac{9}{200}]\;Gallons\;of\;Gas

⇒ Andre drives (420 × 1 Mile) using [\frac{420\times9}{200}]\;Gallons\;of\;Gas

⇒ Andre drives 420 Miles using 18.9 Gallons of Gas

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the scale on the map is 1 cm : 80 km . if two cities are 4 cm apart on the map, what is the actual distance between the cities?
jarptica [38.1K]

Hello there! Your answer would be '<em>the actual distance between the cities is 320 kilometers</em>'.


Okay, so to solve this, we can use unit rates. We know that for every one centimeter we have eighty kilometers. So, whatever we multiply the centimeter value by, we can multiply the kilometer value by the same number and get our answer.

So if the centimeter value is 4, multiply the kilometer value by 4.

80 x 4 = 320

This means that the cities are 320 kilometers apart, and you have your answer!

Hope this helps, and have a great day!

8 0
3 years ago
14 Type the correct answer in each box. Use numerals instead of words. a Ava, Lucas, and Maria are playing a game where they pas
jeka94

Answer:

  • Maria–Ava: 15.7 feet
  • Lucas–Maria: 10.1 feet
  • angle at Maria: 50°

Step-by-step explanation:

The cosine and tangent functions are useful here. The relevant relations are ...

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

__

The distance from Maria to Ava (ma) is the hypotenuse of the triangle, so we have ...

  cos(40°) = 12/ma

  ma = 12/cos(40°) ≈ 12/0.76604 ≈ 15.7 . . . feet

__

The distance from Lucas to Maria (ml) is the side opposite the given angle, so we have ...

  tan(40°) = ml/12

  ml = 12·tan(40°) ≈ 12·0.83910 ≈ 10.1 . . . feet

__

The angle formed at Maria's position is the complement of the other acute angle in the right triangle:

  M = 90° -40° = 50°

In summary, ...

  • Maria–Ava: 15.7 feet
  • Lucas–Maria: 10.1 feet
  • angle at Maria: 50°

5 0
2 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
A manufacturer produces cherry, peppermint, cinnamon, and orange-flavored gum. Each flavor is available with sugar or sugar-free
Semenov [28]

Answer: The total number of different types of labels will the manufacturers have to produce = 24.

Step-by-step explanation:

Given: Choices for flavours = 4

Choices for sugar = 2  {either sugar or sugar free}

Choices for the qunatity = 3

By Fundamental counting principle,

Total number of different types of labels will have to produce = (Choices for flavors) x (Choices for sugar)x (Choices for the quantity )

= 4 x  2x 3

=24

Hence, the total number of different types of labels will the manufacturers have to produce = 24.

4 0
3 years ago
A gallon of Moo Milk costs $5.12. What is the price, in dollars, of an 8 ounce glass of Moo Milk?
Lesechka [4]

Answer:

Your answer is 42

please mark me brain list

8 0
3 years ago
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