Answer:
She will run a distance of 1095.78 miles per year.
Number of days in a year = 365.25
Number of days in a week = 7
Number of weeks in a year = 365.25/7 = 52.18 weeks.
Tomika plans to run 84 miles in 4 weeks.
Distance run by Tomika in 1 week = 84/4 = 21 miles.
Distance run by Tomika in 1 year = 21*52.18 = 1095.78 miles
So she will run a distance of 1095.78 miles per year.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Provide problems and we're here to help.
Well, you have two cubes with six numbers on each, you figure out you have twelve numbers. so there are 6/12 if a chance
Answer:
8 pens
Step-by-step explanation:
<h2><u>Finding the number of pens bought </u></h2>
pencil costs 0.27
pen costs 0.32
6 * pencils + x pens = 4.18
6 * 0.27 + x * 0.32 = 4.18
1.62 + 0.32x = 4.18
0.32x = 4.18 - 1.62
0.32x = 2.56
x = 2.56/0.32
x = 8
<u>hence 8 pens were bought </u>
Answer:
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution should be used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 28 - 1 = 27
80% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 27 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.314
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.6 - 0.646 = $33.954
The upper end of the interval is the sample mean added to M. So it is 34.6 + 0.646 = $35.246
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.