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ohaa [14]
3 years ago
6

I need help with this homework

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0
X 0 1 2 3 4 5
y -1 1 3 5 7 9

Hope this helps
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Which of the following is a monomial ? 9/x 11x2 20x9-7x 20x -14
irakobra [83]

Answer: 11x^2

Step-by-step explanation:

I suppose that the options are:

a) 9/x

b) 11x^2

c) 20x^9-7x

d) 20x -14

First, a polynomial is something like:

aₙx^n + .... + a₂*x^2 + a₁*x^1 + a₀*x^0

Where n is the degree of the polynomial,  the therms a are the coefficients, and aₙ is the leading coefficient.

Depending on the number of terms of the polynomial, it takes different names.

If we have only one term, it is called a monomial, if it has two terms, it is called a binomial, and so on.

So if we want to find a monomial, then we need to look at the options with only one term.

The options with only one term are options a and b.

But option a is a quotient (we have a negative power of x: 9/x = 9*x^-1)

So this is not a polynomial, then the correct option is option b.

8 0
3 years ago
Solution of <br><br> (a+b) x^{2} + cx + a = 1<img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmidd
natulia [17]
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8 0
3 years ago
NEED HELP ON THIS ASAP
Wittaler [7]

Answer:

CosF=A/H

CosF=24/25

CosF=0.96

F=Cos^-1(0.96)

F=16°

6 0
3 years ago
S minus 26 divided by negative 23 equals negative 2
Slav-nsk [51]
Next time please state your goal:  what are you trying to find / calculate / do ?

Find s, if

s-26
------ = -2      Mult. both sides by -23, to obtain:    s-26 = 46
 -23              Simplifying,                                       s = 72 (answer)
4 0
4 years ago
Determine whether the ordered pair is a solution of the given system
Angelina_Jolie [31]

Answer:

yes

Step-by-step explanation:

To determine if the ordered pair is a solution, substitute the x- coordinate into the right side of the inequality and compare the value obtained to the left side.

2x + 4 = 2(2) + 4 = 4 + 4 = 8 and 12 > 8

3x + 7 = 3(2) + 7 = 6 + 7 = 13 and 12 < 13

Both inequalities are true for (2, 12), thus it is a solution

7 0
4 years ago
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