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lana66690 [7]
3 years ago
10

I kinda need help With this ‍

Mathematics
1 answer:
vredina [299]3 years ago
3 0
Distance formula = √(x2-x1)^2 + (y2-y1)^2
so
√(2-(-4))^2 + (0-1)^2
= √(6)^2 + (-1)^2
= √36 + 1
= √37
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You have $6000 with which to build a rectangular enclosure with fencing. The fencing material costs $30 per meter. You also want
Roman55 [17]
Refer to the figure shown below.
x =  the width of the rectangle (meters)
y = the height of the rectangle (meters(

The fencing for the perimeter of the rectangle costs  $30 per meter.
The two inner partitions cost $25 per meter.

The total cost of the fencing is
C = 2(x+y)*$30 + 2y*$25
   = 60(x+y) + 50y 
   = 60x + 110y

Because the amount available to spend is $600, therefore
60x + 110y = 6000
or
6x + 11y = 600
That is,
y = (600 - 6x)/11              (1)

The area is
A = x*y                           (2)

Substitute (1) into (2).
A = (x/11)*(600 - 6x) = (1/11)*(600x - 6x²)

To maximize A, the derivative of A with respect to x is zero.
That is,
600 - 12x = 0
x = 600/12 = 50
From (1), obtain
y = (1/11)*(600 - 6*50) = 300/11 = 27.273

Because the second derivative of A with respect to x is negative, x=50, y = 27.273 will yield the maximum area.

The maximum area is
50*27.273 = 1363.64 m² = 1364 m² (nearest integer)

Answer: 1364 m² (nearest integer)

5 0
3 years ago
URGENT 25 POINTS MATH EQUATION PLEASE NO POINT STEAL!
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6 0
3 years ago
Solve the expression (7th grade math):<br><br> 17 - 1/5x + 2/3x - 92 + 7/10x
Rzqust [24]

Answer:

The answer is 7/6x - 75.

Step-by-step explanation:

17 - 1/5x +2/3x - 92 + 7/10x

17 - 6/30x + 20/30x - 92 + 21/30x

-6/30x + 20/30x + 21/30x = 35/30x or 7/6x

17 - 92 = -75

7/6x - 75

3 0
2 years ago
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