Answer:
<h2>42 and -16</h2>
Step-by-step explanation:
![m,\ n-the\ numbers\\\\\text{The equations:}\\\\(1)\qquad n+2m=10\\(2)\qquad n+m=26\\\\\text{subtract both sides of the equations}\\\\(n+2m)-(n+m)=10-26\\\\n+2m-n-m=-16\qquad\text{combine like terms}\\\\(n-n)+(2m-m)+-16\\\\\boxed{m=-16}\\\\\text{Put the value of m to (2)}:\\\\n+(-16)=26\\\\n-16=26\qquad\text{add 16 to both sides}\\\\\boxed{n=42}](https://tex.z-dn.net/?f=m%2C%5C%20n-the%5C%20numbers%5C%5C%5C%5C%5Ctext%7BThe%20equations%3A%7D%5C%5C%5C%5C%281%29%5Cqquad%20n%2B2m%3D10%5C%5C%282%29%5Cqquad%20n%2Bm%3D26%5C%5C%5C%5C%5Ctext%7Bsubtract%20both%20sides%20of%20the%20equations%7D%5C%5C%5C%5C%28n%2B2m%29-%28n%2Bm%29%3D10-26%5C%5C%5C%5Cn%2B2m-n-m%3D-16%5Cqquad%5Ctext%7Bcombine%20like%20terms%7D%5C%5C%5C%5C%28n-n%29%2B%282m-m%29%2B-16%5C%5C%5C%5C%5Cboxed%7Bm%3D-16%7D%5C%5C%5C%5C%5Ctext%7BPut%20the%20value%20of%20m%20to%20%282%29%7D%3A%5C%5C%5C%5Cn%2B%28-16%29%3D26%5C%5C%5C%5Cn-16%3D26%5Cqquad%5Ctext%7Badd%2016%20to%20both%20sides%7D%5C%5C%5C%5C%5Cboxed%7Bn%3D42%7D)
The sum of the angles in a heptagon is 900°, so we would add the real numbers that we have here:
121°+139°+125°+126°+158°+120°=789°
x would equal the remaining value:
x=900-789
x=111°
Answer:
Step-by-step explanation:
1) 2x+ 4 = 10
2x = 6
x = 3 (3 is the answer)
2) we have to substitute y with 3 and z with 4
3.75*3 + 6.50*4 ≥ 50
11,25 + 26 ≥ 50
37.25 ≥ 50
so the answer is no, because the total will be $37.25
3) 12k + 2 < 12
12k < 10
k < 5/6
3/4 < 5/6 so the answer is true
4) we have to try the options
a) 3*4 + 4*2 + 6 = 26
12 + 8 + 6 = 26
26 = 26 (true)
b) 3*5 + 4*6 + 6 = 26
15 + 24 + 6 = 26
45 = 26 (false)
c) 3*4 + 4*3 + 6 = 26
12 + 12 + 6 = 26
30 = 26 (false)
d) 3*3 +4*5 + 6 = 26
9 + 20 + 6 = 26
35 = 26 (false)
so the answer is x=4 , y=2
5) 3a + 4 ≥ 13
3a ≥ 9
a ≥ 3
so the answer is {3,4.5,5}