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mash [69]
3 years ago
5

In a square handkerchief having a side measurement 30 cm the portion 5

Mathematics
1 answer:
olasank [31]3 years ago
4 0

Step-by-step explanation:

the area of the red coloured portion =

(30×30) -(20×20)

= 900-400

= 500 cm²

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Step-by-step explanation:

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Answer:


Step-by-step explanation:

Problem One (left panel)

<em><u>Question A</u></em>

  • The y intercept happens when x = 0
  • That being said, the y intercept is 50. It was moving when the timing began.

<em><u>Question B</u></em>

The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2  miles / hour^2 (you have a slight acceleration.

<em><u>Question C</u></em>

  • 60 = a + (n-1)d
  • 60 =  50 + (n - 1)*2
  • 10/2 = (n - 1)*2/2
  • 5 = n - 1
  • 6 = n

The way I have done it the domain is n from 1 to 6

Question 2 (Right Panel)

<em><u>Question A</u></em>

The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.

  • f(0) = ax + b
  • -3 = a*0) + b
  • b = - 3
  • So far what you have is
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  • - 6 = a(-1) - 3             add 3 to both sides
  • -6 +3 = a(-1) -3 + 3
  • -3 = a*(-1)                  Divide by - 1
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  • f(x) has a slope of 3
  • g(x) has a slope of 4

<em><u>Part B</u></em>

  • f(x) has a y intercept of - 3
  • g(x) has a y intercept of -5
  • f(x) has the greater y intercept.
  • -3 > - 5
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4 years ago
A square sheet of art paper has an area of 625 square inches. What is the minimum side length of an easel that supports the whol
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If the area of the paper is 625 sq in, the length of one side of this square is sqrt(625 sq in), or 25 inches.  That's the min. side length of an easel that is to support the whole sheet of paper along its lowest side.
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