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gtnhenbr [62]
2 years ago
15

Complete the transformation below:

Mathematics
1 answer:
Verdich [7]2 years ago
4 0

Answer:

a c

Step-by-step explanation:

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PLEASSS HELP!!!!!!! I REALLY NEED HELP!!
loris [4]

Answer:

\underline{ \boxed{x = 11} } \\ \underline{ \boxed{ABE = 55}}

Step-by-step explanation:

if \: the \: question \: is \to \\  \overline{AZ} \: \perp \: \overline{CD}, \: m \angle{ABE} = 5x, \\ and  \\ \: m \angle{EBD } = 3x + 2\\ but \: m \angle{EBD }  +  m \angle{ABE} = 90 \\ hence \to \\ (3x + 2) + (5x) = 90 \\ 8x + 2 = 90 \\ 8x = 90 - 2 \\ 8x = 88 \\ x =  \frac{88}{8}  \\ \boxed{ x = 11} \\  \\ if \: x = 11, \: then \to \\ m \angle{ABE} = \: 5x = 5(11) \\  \boxed{m\angle{ABE} =55}

6 0
3 years ago
What is the solution of x+8/5x-1>0?
DerKrebs [107]

Answer:

x<-8 or x>1/5

Step-by-step explanation:

\frac{x+8}{5x-1} >0

First we replace > symbol by = sign

\frac{x+8}{5x-1} =0

To solve for x we multiply 5x-1 on both sides

x+8 =0

x=-8

5x-1=0 solve for x

x= 1/5

WE got two values x=-8  and x= 1/5

Now we make a number line and check with each interval

x<-8,  -8<x<1/5,  x>1/5

Pick x= -9 and check with the given inequality

\frac{-9+8}{5(-9)-1} >0

1/46 >0 is true, so x<-8 satisfies our inequality

Pick x= 0 and check with the given inequality

\frac{0+8}{5(0)-1} >0

-8 >0 is false , -8<x<1/5 does not satifies our inequality

Pick x= 2 and check with the given inequality

\frac{2+8}{5(2)-1} >0

10/9>0 is true , x>1/5  satisfies our inequality

3 0
3 years ago
Read 2 more answers
One number is 1/2 of another the sum of the number is 72 find the numbers
Anton [14]
The answer for the question is 36 , 36
5 0
3 years ago
Which is the rationalized form of the expression. A, B , C, or D?
grin007 [14]

Answer:

C

Step-by-step explanation:

Multiply the top and bottom, both by sqrtx-sqrt5. This is in order to rationalize the denominators.

You get answer C.

3 0
2 years ago
Find all of the zeros of the function and write the polynomial as the product of linear factors.
Tomtit [17]

Answer:

(x+6i)(x-6i)(x+1)

So the zeroes are 6i, -6i, -1

Step-by-step explanation:

Factor by grouping

h(x) = x^2(x+1) + 36(x+1)

h(x) = (x^2+36)(x+1)

3 0
3 years ago
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